Question

A girl throws a water filled balloon on the eve of Holi with a velocity 12 ms^-1 at an angle of 60⁰ with the horizontal. It hits a car at the same height (of throw) approaching her at 15 ms^-1. Find the distance of the car from her.

• A. 13 m
• B. 31 m
• C. 44 m
• D. 18 m

Answer 1

Answer: (C)

44 m

Answer 2

T = $\frac{2u\sin\theta}{g} = \frac{2 \times 12 \times \left( \sqrt{3}/2 \right)}{10} = 2.07s;$

R = $\frac{u\sin\theta}{g} = \frac{2 \times 12 \times \sqrt{3}}{10 \times 2} = 13m$s

Distance of car from here = 13 + 15(2.07) = 44 m