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Question: A girl standing on a stationary lift (open from above) throws a ball upwards with initial speed 50 m...

A girl standing on a stationary lift (open from above) throws a ball upwards with initial speed 50 m s-1. The time taken by the ball to return to her hands is

(Take g = 10 m s-2)

A

5 s

B

10 s

C

15 s

D

20 s

Answer

10 s

Explanation

Solution

Using,

Here

∴0=50t+12×(−10)t2=50t−5t2\therefore 0 = 50 \mathrm { t } + \frac { 1 } { 2 } \times ( - 10 ) \mathrm { t } ^ { 2 } = 50 \mathrm { t } - 5 \mathrm { t } ^ { 2 }