Question

A gaseous system undergoes a change of state from (1) to (2) by any of the given path-

path-I or path- II as shown in figure

As per path –I, Dq = – 400 cal and DW = 14 cal

As per path –II, Dq = – 48 cal.

Therefore work done, DW in path –(II) is-

• A. – 338 cals
• B. – 366 cals
• C. – 434 cals
• D. – 462 cals

Answer 1

Answer: (A)

– 338 cals

Answer 2

For path –I DE_I = Dq + DW = – 400 + 14

= – 386 cals

For path –II, DE_II = DE_I = – 48 + DW

\ DW = – 386 + 48 = –338 cal