Question
Question: A gaseous mixture contains oxygen and nitrogen in 1:4 ratio by weight. The ratio of their number of ...
A gaseous mixture contains oxygen and nitrogen in 1:4 ratio by weight. The ratio of their number of molecules is:
A.1:4
B.1:8
C.7:32
D.3:16
Solution
Mole concept gives the relationship between the number of moles, weight and molar mass of the compound.
-It is the most convenient method to express the amount of a substance
-Molar mass is calculated by adding up the atomic masses of the element combined to form a molecule.
Formula used:
n=MW
where, n is the number of moles, W is the weight of the compound and M is the molar mass of the compound.
Number of molecules =6.023×1023× moles
Complete step by step solution:
The number of moles is defined as the weight per molar mass. It is a unit of measurement which is used to express the amount of reactants and products in a chemical reaction.
In this question, a gaseous mixture of oxygen and nitrogen is in the ratio of 1:4 by weight.
Molar mass of oxygen (O2) is 32 and that of nitrogen (N2) is 28 .
The molar ratio of oxygen (O2) : nitrogen (N2) will be:
MO2WO2:MN2WN2
Now, substituting the values in the above formula, we get,
The molar ratio of oxygen (O2) : nitrogen (N2) will be:
321:284
On further solving, we get,
⇒321:71
This is equation (1)
To calculate the number of moles, formula used is:
n=MW
where, n is the number of moles, W is the weight of the compound and M is the molar mass of the compound.
Now, applying this formula in equation (1) , we get,
Ratio of their molecules:
⇒326.023×1023:76.023×1023
On further solving, the final ratio would be,
⇒7:32
Therefore, the correct option is (C) 7:32 .
Note:
-Avogadro’s number is defined as the proportionality factor that tells the relationship between the number of constituent particles with the amount of substance in a sample. Its SI unit is mol−1 . It is denoted with a symbol, NA .
NA=6.023×1023mol−1
-It is the number of units in a mole of any substance.