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Question: A gaseous mixture contains 56 g of \(\mathrm { CH } _ { 4 }\). The total pressure of the mixture is ...

A gaseous mixture contains 56 g of CH4\mathrm { CH } _ { 4 }. The total pressure of the mixture is 720 mm Hg. The partial pressure of CH4\mathrm { CH } _ { 4 } is

A

180 mm

B

360 mm

C

540 mm

D

720 mm

Answer

180 mm

Explanation

Solution

p(CH4)=16/165/28+44/44+16/16×720=12+1+1×720=14×720=180 mm\mathrm { p } \left( \mathrm { CH } _ { 4 } \right) = \frac { 16 / 16 } { 5 / 28 + 44 / 44 + 16 / 16 } \times 720 = \frac { 1 } { 2 + 1 + 1 } \times 720 = \frac { 1 } { 4 } \times 720 = 180 \mathrm {~mm}