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Question: A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio C<sub>p</sub>/C<sub>v</su...

A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio Cp/Cv of the mixture is –

A

1.4

B

1.54

C

1.59

D

1.62

Answer

1.62

Explanation

Solution

µ1 = 164\frac{16}{4}= 4, µ2 = 1632=12\frac{16}{32} = \frac{1}{2}

(Cp)mix = μ1Cp1+μ2Cp2μ1+μ2\frac{\mu_{1}C_{p_{1}} + \mu_{2}C_{p_{2}}}{\mu_{1} + \mu_{2}}

(Cv)mix = μ1Cv1+μ2Cv2μ1+μ2\frac{\mu_{1}C_{v_{1}} + \mu_{2}C_{v_{2}}}{\mu_{1} + \mu_{2}}; gmix = (Cp)mix(Cv)mix\frac{(C_{p})_{mix}}{(C_{v})_{mix}}