Question

A gas $(X)$ is obtained when copper reacts with dilute $HNO_3$. The gas thus formed reacts with oxygen to give brown fumes of $(Y)$. $(Y)$ when dissolved in water gives an important acid $(Z)$ and the gas $(X)$. $X$ , $Y$ and $Z$ respectively are

• A. $NO ; NO_2; HNO_3$
• B. $NO_2 ; NO ; HNO_3$
• C. $N_2O ; NO ; HNO_2$
• D. $NO ; N_2O ; HNO_3$

Answer 1

Answer: (A)

$NO ; NO_2; HNO_3$

Answer 2

${3Cu + 8HNO3_{(dil)} \to 3Cu(NO3)_2}$ $+\,\underset{\text{(X)}}{ {2NO}}\,+ {4H2O}$ ${2NO +O2 <=>}$ $\underset{\text{(Y)}}{ {2NO2}}$ $\underset{\text{(Y)}}{ {3NO2}}+ {H2O} \to$ $\underset{\text{(Z)}}{ {2HNO3}}+$ $\underset{\text{(X)}}{ {NO}}$