Question
Question: A gas mixture contains \[1g{\text{ }}{H_2}\] and \[1g{\text{ }}{H_e}\] temperature of the gas mixtu...
A gas mixture contains 1g H2 and 1g He temperature of the gas mixture is increased from 0∘ to 100∘C an isobaric process. Then find the given heat of the gas mixture. [γH2=35,γHe=57,R=2cal/mol−K]
(A)124cal
(B)327cal
(C)218cal
(D)475cal
Solution
By using the heat capacity ratio we will find the constant volume (CV). To find the value of constant pressure (CP), we will use the mayor’s relation. Through the formula of enthalpy change, we will find the heat of the gas mixture.
Formulae used:
γ=CVCP
CP−CV=R (Mayor’s relation)
H=nCPΔT
Complete step by step answer:
Specific heat capacity can be given by
γ=CVCP
γ−1=CVCP−CV=CVR
⇒CV=γ−1R=4567−1R
⇒CV=2245R
According to the mayor’s relation,
⇒CP=R+CV=2267R
As per the data given in the question, the enthalpy change can be given by
⇒ΔT=100K
⇒H=nCPΔT=0.75×2267×2×100=475cal
Hence, the right option is in option (D).
Additional information:
Enthalpy is the sum of the internal energy and the product of pressure and volume given by the equation:
H=E+PV . Where, E = internal energy
P = pressure
V = volume
H= Enthalpy
When a process occurs at constant pressure, the heat evolved (either released or absorbed) is equal to the change in enthalpy.
The heat capacity ratio, also known as the adiabatic index. It is the ratio of the heat capacity at constant pressure (CP) to heat capacity at constant volume (CV). It is sometimes also known as the isentropic expansion factor and is denoted by (gamma) for an ideal gas .
γ=CVCP
Note: Mayor’s formula states that the difference between the specific heat of a gas at constant pressure and its specific heat at constant volume is equal to the gas constant divided by the molecular weight of the gas.