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Question: A gas mixture consists of molecules of type 1, 2 and 3 with molar masses \(m_{1} > m_{2} > m_{3}\). ...

A gas mixture consists of molecules of type 1, 2 and 3 with molar masses m1>m2>m3m_{1} > m_{2} > m_{3}. vrmsv_{rms}andKˉ\bar{K} are the rms speed and average kinetic energy of the gases. Which of the following is true

A

(vrms)1<(vrms)2<(vrms)3(v_{rms})_{1} < (v_{rms})_{2} < (v_{rms})_{3}and(Kˉ)1=(Kˉ)2=(Kˉ)3(\bar{K})_{1} = (\bar{K})_{2} = (\bar{K})_{3}

B

(vrms)1=(vrms)2=(vrms)3(v_{rms})_{1} = (v_{rms})_{2} = (v_{rms})_{3}and(Kˉ)1=(Kˉ)2>(Kˉ)3(\bar{K})_{1} = (\bar{K})_{2} > (\bar{K})_{3}

C

(vrms)1>(vrms)2>(vrms)3(v_{rms})_{1} > (v_{rms})_{2} > (v_{rms})_{3}and(Kˉ)1<(Kˉ)2>(Kˉ)3(\bar{K})_{1} < (\bar{K})_{2} > (\bar{K})_{3}

D

(vrms)1>(vrms)2>(vrms)3(v_{rms})_{1} > (v_{rms})_{2} > (v_{rms})_{3}and(Kˉ)1<(Kˉ)2<(Kˉ)3(\bar{K})_{1} < (\bar{K})_{2} < (\bar{K})_{3}

Answer

(vrms)1<(vrms)2<(vrms)3(v_{rms})_{1} < (v_{rms})_{2} < (v_{rms})_{3}and(Kˉ)1=(Kˉ)2=(Kˉ)3(\bar{K})_{1} = (\bar{K})_{2} = (\bar{K})_{3}

Explanation

Solution

The rms speed depends upon the molecular mass vrms1Mv_{rms} \propto \frac{1}{\sqrt{M}} but kinetic energy does not depends on it EM0E \propto M^{0}

In the problem m1>m2>m3m_{1} > m_{2} > m_{3}(vrms)1<(vrms)2<(vrms)3(v_{rms})_{1} < (v_{rms})_{2} < (v_{rms})_{3}but (Kˉ1)=(Kˉ2)=(Kˉ3)({\bar{K}}_{1}) = ({\bar{K}}_{2}) = ({\bar{K}}_{3})