Question
Question: A gas mixture consists of \( 3\cdot 0 \) mole of hydrogen and \( 2\cdot 0 \) mole of helium at absol...
A gas mixture consists of 3⋅0 mole of hydrogen and 2⋅0 mole of helium at absolute temperature T considering all vibrational modes (assuming internal energy at T=0), the total energy of system is
(A) 11⋅5 RT
(B) 10⋅5 RT
(C) 13⋅5 RT
(D) 15 RT
Solution
We have given Monoatomic gas helium and diatomic gas hydrogen. Use the following formula: specific heat capacity at constant volume for monatomic gas is 23R .
Specific heat capacity at constant volume for diatomic gas is 25R
The total energy of the system is given by.
n1c1vT+n2c2vT
Here, n1 is no. of moles for one gas [hydrogen],
C1v is specific heat capacity [hydrogen],
n2 is no. of moles for helium gas ,
C2v is specific heat capacity for helium gas.
Complete step by step solution
We have given, Hydrogen gas which is diatomic. C1v specific heat capacity at constant volume,
25R .
Here, R is gas constant.
No, of moles of hydrogen gas (n1)=3
Now, for helium gas which is monoatomic. C2v specific heat capacity for helium gas at constant volume is given by, 23R .
No. of moles for helium gas = 2
Now, both the gases are mixed, then total internal energy of system is given by,
n1c1vT+n2c2vT ---------- (1)
Put all the above values in eq. (1).
(3)(25R)T+2(23R)T
215RT+26RT
(215+6)RT=221RT=10.5RT
Hence, total energy of the system is 10⋅5 RT.
Note
Monoatomic gases consist of only one atom, it is capable of translatory motion and hence 3 degrees of freedom. Diatomic gases like hydrogen, Nitrogen, Oxygen, etc. have two atoms in it. The molecule is capable of translatory motion of its centre of mass as well as the molecule can rotate about its centre of mass. Therefore, a diatomic molecule has in all 5 degrees of freedom, three due to translation and two due to rotation.