Question

A gas is filled in a container at pressure P0. If the mass of molecules is halved and their rms speed is doubled, then the resultant pressure would be

• A. 2P0
• B. 4P0
• C. $\frac{P_{0}}{4}$
• D. $\frac{P_{0}}{2}$

Answer 1

Answer: (A)

2P0

Answer 2

Using, $P = \frac{1}{3}\rho{v^{2}}_{rms} = \frac{1}{3}\frac{mN}{V}{v^{2}}_{rms}$

$\therefore P \propto m{v^{2}}_{rms}$

As m is halved $v_{rms}$is doubled $P_{0}$ becomes twice $= 2P_{0}$