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Question: A gas is expanded to double its volume by two different processes. One is isobaric and the other is ...

A gas is expanded to double its volume by two different processes. One is isobaric and the other is isothermal. Let W1 and W2 be the respective work done, then

A

W2=W1ln(2)W_{2} = W_{1}\ln(2)

B

W2=W1ln(2)W_{2} = \frac{W_{1}}{\ln(2)}

C

W2=W12W_{2} = \frac{W_{1}}{2}

D

Data is insufficient

Answer

W2=W1ln(2)W_{2} = W_{1}\ln(2)

Explanation

Solution

Suppose initial temp is T0

Isobaric :

W1 = nRDT = nR(2T0 – T0) = nRT0

W2 = nRT0 lnV2V1\mathcal{l}n\frac{V_{2}}{V_{1}} = nRT0ln2