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Question: A gas is compressed at a constant pressure of \(50N{m^{ - 2}}\) from a volume \(10{m^3}\) to a volum...

A gas is compressed at a constant pressure of 50Nm250N{m^{ - 2}} from a volume 10m310{m^3} to a volume of 4m34{m^3}. If 100J100J of heat is added to the gas, then its internal energy
A. increases by 400J400J
B. increases by 200J200J
C. decreases by 400J400J
D. decreases by 200J200J

Explanation

Solution

This problem can be solved simply by applying the concept of the first law of thermodynamics. Applying the above values in the first law equation, we can obtain the value of the change in internal energy.

Formulas used
dQ=dU+dWdQ = dU + dW where dQdQ is the heat absorbed by the system, dUdU is the increase in the internal energy and dWdW is the external work done.
dW=PdVdW = PdV where PP is the pressure and dVdV is change in volume of the system.

Complete step by step answer
According to the first law of thermodynamics, when heat energy is supplied to a system, a part of it is used to increase the internal energy of the system and the rest of it is used to perform external work.
The statement for first law of thermodynamics is given as,
dQ=dU+dWdQ = dU + dW where dQdQ is the heat absorbed by the system, dUdU is the increase in the internal energy and dWdW is the external work done.
Now, dWdW can be written as PdVPdV where PP is the pressure and dVdV is change in volume of the system.
Thus, the above equation becomes,
dQ=dU+PdVdQ = dU + PdV
dU=dQPdV\Rightarrow dU = dQ - PdV
The volume of the gas given changes from 10m310{m^3} to 4m34{m^3}
So, V1=10m3{V_1} = 10{m^3} and V2=4m3{V_2} = 4{m^3}
dV=(V2V1)=(410)m3 dV=6m3 \begin{gathered} dV = \left( {{V_2} - {V_1}} \right) = \left( {4 - 10} \right){m^3} \\\ \Rightarrow dV = - 6{m^3} \\\ \end{gathered}
Therefore,
\begin{gathered} dU = 100 - \left\\{ {50 \times \left( { - 6} \right)} \right\\}J \\\ \Rightarrow dU = 100 + 300 \\\ \Rightarrow dU = 400J \\\ \end{gathered}
This means that the internal energy of the gas increases by 400J400J

Thus, the correct option is A.

Note: The first law establishes an exact relation between heat and other forms of energy. However, it cannot state the condition under which a system can transform its heat energy into work. Also cannot specify how much of the heat energy can be converted to work. The internal energy of a system is a state function, which means that it only depends upon the initial and final state and is independent of the path.