Solveeit Logo

Question

Chemistry Question on Thermodynamics

A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5atm2.5\, atm from an initial volume of 2.50L2.50\, L to a final volume of 4.50L4.50\, L. The change in internal energy ΔU\Delta U of the gas in joules will be

A

-500J

B

-505J

C

#ERROR!

D

1136.25J

Answer

-505J

Explanation

Solution

ΔU=q+w\Delta U = q + w

For adiabatic process, q=0q=0
ΔU=w\therefore \Delta U = w
=PΔV=- P \cdot \Delta V
=2.5atm×(4.52.5)L=-2.5\, atm \times(4.5-2.5)\, L
=2.5×2Latm=-2.5 \times 2\, L - atm
=5×101.3J=-5 \times 101.3\, J
=506.5J=-506.5\, J
505J\approx-505\, J