Question

A gas has a vapour density $11.2.$ The volume occupied by $lg$ of the gas at NTP is :

• A. 1 L
• B. 11.2 L
• C. 22.4 L
• D. 4 L

Answer 1

Answer: (A)

1 L

Answer 2

(i) Molecular weight $=2 \times$ vapour density
(ii) Molecular weight in gram $=22.4 L$ at STP
Given vapour density $=11.2$ Molecular weight $=2 \times 11.2=22.4$
$\therefore 22.4 \,g$ of gas occupies $=22.4\, L$ at STP
$\therefore 1 \,g$ of gas occupies $=\frac{22.4}{22.4} \times 1$
$=1\, L$ at $STP$