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Question: A gas expands \(0.25m^{3}\) at constant pressure \(10^{3}N/m^{2}\), the work done is...

A gas expands 0.25m30.25m^{3} at constant pressure 103N/m210^{3}N/m^{2}, the work done is

A

2.5 ergs

B

250 J

C

250 W

D

250 N

Answer

250 J

Explanation

Solution

ΔW=PΔV=103×0.25=2506muJ\Delta W = P\Delta V = 10^{3} \times 0.25 = 250\mspace{6mu} J