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Question

Question: A gas diffuse 1/5 times as fast as hydrogen. Its molecular weight is....

A gas diffuse 1/5 times as fast as hydrogen. Its molecular weight is.

A

50

B

25

C

(p+aVm2)(Vm)=RT\left( p + \frac{a}{V_{m}^{2}} \right)(V_{m}) = RT

D

pVm=RTpV_{m} = RT

Answer

50

Explanation

Solution

MV\frac{M}{V}

PMRT\frac{PM}{RT}; P=0.5atm,T=600KP = 0.5atm,T = 600K