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Question

Chemistry Question on Thermodynamics

A gas can expand from 100 mL to 250 mL undera constant pressure of 2 atm. The work done by the gas is

A

30.38 joule

B

25 joule

C

5 k joule

D

16 joule

Answer

30.38 joule

Explanation

Solution

Δ\DeltaV = 250 mL - 100 mL = 150 mL = 0.15 L PextP_{ext} = 2 atm W = -Pext×ΔP_{ext} \times \Delta V = - (0.15 L) ×\times (2 atm) = - 0.3 Latm. = 0.3×1.01325×102J-0.3 \times 1.01325 \times 10^2J = 30.3975 J.