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Question

Physics Question on Thermodynamics

A gas can be taken from AA to BB via two different processes ACBACB and ADBADB. When path ACBACB is used 60J60\, J of heat flows into the system and 30J30\, J of work is done by the system. If path ADBADB is used work done by the system is 10J10\, J. The heat Flow into the system in path ADBADB is :

A

80 J

B

20 J

C

100 J

D

40 J

Answer

40 J

Explanation

Solution

ΔQACB=ΔWACB+ΔUACB\Delta Q_{ACB} = \Delta W_{ACB} + \Delta U_{ACB}
  60J=30J+ΔUACB\Rightarrow \; 60 J = 30 J + \Delta U_{ACB}
  ΔUACB=30  J\Rightarrow \; \Delta U_{ACB} = 30 \;J
  ΔUADB=ΔUACB=30  J\Rightarrow \; \Delta U_{ADB} = \Delta U_{ACB } = 30 \; J
ΔQACD=ΔUACB+ΔWADB\Delta Q_{ACD} = \Delta U_{ACB} + \Delta W_{ADB}
= 10J+30J=40J10\, J + 30\, J = 40\, J