Question

A gas at 27⁰C has a volume V and pressure P. On heating its pressure is doubled and volume becomes three times. The resulting temperature of the gas will be

• A. 1800⁰C
• B. 162⁰C
• C. 1527⁰C
• D. 600⁰C

Answer 1

Answer: (C)

1527⁰C

Answer 2

From ideal gas equation $PV = \mu RT$ we get

$\frac{T_{2}}{T_{1}} = \left( \frac{P_{2}}{P_{1}} \right)\left( \frac{V_{2}}{V_{1}} \right) = \left( \frac{2P_{1}}{P_{1}} \right)\left( \frac{3V_{1}}{V_{1}} \right) = 6$

∴ $T_{2} = 6T_{1} = 6 \times 300 = 1800K = 1527{^\circ}C.$