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Question

Physics Question on work, energy and power

A gardener pushes a lawn roller through a distance 20m20\,m . If he applies a force of 20kgwt20\,kg\,wt in a direction inclined at 6060^{\circ} to the ground, the work done by him is

A

1960J1960\,J

B

196J196\,J

C

1.96J1.96\,J

D

196kJ196\,kJ

Answer

1960J1960\,J

Explanation

Solution

Given, F=20kgwt=20×9.8NF=20\, kg -w t=20 \times 9.8 \,N
θ=60\theta=60^{\circ} and s=20ms=20\, m
Work done =F.scosθ=F . s \cos \theta
=20×9.8×20×cos60=20 \times 9.8 \times 20 \times \cos 60^{\circ}
=1960J=1960\, J