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Question

Physics Question on Electrical Instruments

A galvanometer with a scale divided into 100100 equal divisions has a current sensitivity of 1010 divisions per milliampere and a voltage sensitivity of 22 divisions per millivolt. The galvanometer resistance will be

A

4Ω 4 \, \Omega

B

5Ω 5 \, \Omega

C

3Ω 3 \, \Omega

D

7Ω7 \, \Omega

Answer

5Ω 5 \, \Omega

Explanation

Solution

Given: current sensitivity = 10 div/mA and there are 100 division on the scale.
\therefore Current required for full scale deflection.
Ig=110×100mA=10mAI_{g} = \frac{1}{10} \times100\,mA = 10 \,mA
=0.1A= 0.1 A
Also voltage sensitivity = 2 div/mV
\therefore voltage required for full scale deflection
Vg=12×100mVV_{g} = \frac{1}{2} \times100mV
=0.05V= 0.05V
Galvanometer resistance is given by
G=VgIg=0.050.01G = \frac{V_{g}}{I_{g}} = \frac{0.05}{0.01}
=5Ω= 5 \Omega