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Question

Question: A galvanometer of resistance\(70 \Omega\), is converted to an ammeter by a shunt resistance![](https...

A galvanometer of resistance70Ω70 \Omega, is converted to an ammeter by a shunt resistance. The value of its resistance will become

A

0.025Ω0.025 \Omega

B

0.022Ω0.022 \Omega

C

0.035Ω0.035 \Omega

D

0.030Ω0.030 \Omega

Answer

0.030Ω0.030 \Omega

Explanation

Solution

R=RGrsRG+rs\mathrm { R } = \frac { \mathrm { R } _ { \mathrm { G } } \mathrm { r } _ { \mathrm { s } } } { \mathrm { R } _ { \mathrm { G } } + \mathrm { r } _ { \mathrm { s } } }

Here RG=70Ω,rs=0.03Ω\mathrm { R } _ { \mathrm { G } } = 70 \Omega , \mathrm { r } _ { \mathrm { s } } = 0.03 \Omega

R=70×0.0370+0.03=0.02998=0.03Ω\therefore \mathrm { R } = \frac { 70 \times 0.03 } { 70 + 0.03 } = 0.02998 = 0.03 \Omega