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Question: A galvanometer of resistance \(40 \Omega\) gives a deflection of 5 divisions per mA. There are 50 d...

A galvanometer of resistance 40Ω40 \Omega gives a deflection of 5 divisions per mA. There are 50 divisions on the scale. The maximum current that can press through it when a shunt resistance of 2Ω2 \Omega is connected is

A

210 mA

B

15 mA

C

420 mA

D

75 mA

Answer

210 mA

Explanation

Solution

RG=40Ω,Rs=2Ω\mathrm { R } _ { \mathrm { G } } = 40 \Omega , \mathrm { R } _ { \mathrm { s } } = 2 \Omega

Maximum current