Question

A galvanometer of $100 \Omega$ resistance gives full scale deflection when 10 mA of current is passed. To convert it into 10 A range ammeter, the resistance of the shunt required will be

• A. $- 10 \Omega$
• B. $1 \Omega$
• C. $0.1 \Omega$
• D. $0.01 \Omega$

Answer 1

Answer: (C)

$0.1 \Omega$

Answer 2

$S = \frac { i _ { g } G } { i - i _ { g } } = \frac { 100 \times 0.01 } { ( 10 - 0.01 ) } = \frac { 1 } { 10 } = 0.1 \Omega$