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Question

Physics Question on Resistance

A galvanometer having coil resistance 10 Ω shows a full scale deflection for a current of 3 mA. For it to measure a current of 8 A, the value of the shunt should be:

A

103  Ω10^{- 3}\; Ω

B

7.5×103  Ω7.5 \times 10^{- 3}\; Ω

C

6.75×103  Ω6.75 \times 10^{- 3}\; Ω

D

3.75×103  Ω3.75 \times 10^{- 3}\; Ω

Answer

3.75×103  Ω3.75 \times 10^{- 3}\; Ω

Explanation

Solution

Step 1: Given Data: - Galvanometer resistance G=10ΩG = 10 \Omega - Full-scale deflection current Ig=3mA=3×103AI_g = 3 \, \text{mA} = 3 \times 10^{-3} \, \text{A} - Desired current to be measured I=8AI = 8 \, \text{A}

Step 2: Calculate the Shunt Resistance SS: - In order to convert the galvanometer into an ammeter, the shunt resistance SS is given by:

S=IgGIIgS = \frac{I_g \, G}{I - I_g}

Step 3: Substitute the Values:

S=(3×103)×1080.003 S=0.037.9973.75×103ΩS = \frac{(3 \times 10^{-3}) \times 10}{8 - 0.003} \\\ S = \frac{0.03}{7.997} \approx 3.75 \times 10^{-3} \, \Omega

So, the correct answer is : 3.75×103Ω3.75 \times 10^{-3} \, \Omega