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Question

Physics Question on Current electricity

A galvanometer having a coil resistance of 60O60O shows full scale deflection when a current of 1.0 A passes through it. It can be converted unto an ammeter to read currents upto 5.0 A by

A

putting in parallel a resistance of 240O240O

B

putting in series a resistance of 15O15O

C

putting in series a resistance of 240O240O

D

putting in parallel a resistance of 15O15O

Answer

putting in parallel a resistance of 15O15O

Explanation

Solution

iG=(Ii)Si G=(I-i) S where GG is the galvanometer resistance and SS is the shunt used with the ammeter.
1.0×60=(51)S1.0 \times 60=(5-1) S where SS is the shunt used to read a 5A5 A current when the galvanometer can stand by 1A1 A.
S=1.0×604=15ΩS=\frac{1.0 \times 60}{4}=15 \Omega in parallel.