Question
Question: A galvanometer has a coil of resistance 100 ohm and gives a full scale deflection for 30 mA current....
A galvanometer has a coil of resistance 100 ohm and gives a full scale deflection for 30 mA current. If it is to work as a voltmeter of 30 volt range, the resistance required to be added will be
A. 1000Ω B. 900Ω C. 1800Ω D. 500ΩSolution
- Hint: In order to deal with this question we will use the concept to convert the galvanometer into a voltmeter of a given range by connecting a resistance R in series of appropriate resistance according to the problem. Further we will use the formula to find the value of R which is mentioned in solution to get the required answer.
Formula used- V=Ig(G+R)
Complete step-by-step solution -
Given that
Resistance of galvanometer, G=100Q
Current for full scale deflection:
Ig=30mA=30×10−3A
Range of voltmeter, V=30V
To convert the galvanometer into a voltmeter of a given range, a resistance R is connected in series with it as shown in the figure.
From the above figure the voltage V across the points is:
V=Ig(G+R)
The above equation can be written as:
Substitute the given values in above formula we have
∵R=IgV−G ⇒R=30×10−330−100Ω ⇒R=1000Ω−100Ω ⇒R=900ΩHence, the resistance required to be added will be 900Ω
So, the correct answer is option B.
Note- A galvanometer is an electromechanical device which is used to measure and signify electrical current. A galvanometer acts as an actuator in response to electrical current flowing through a coil in a continuous magnetic field, by generating a rotary deflection (of a "pointer"). Galvanometer is an instrument which is used by deflection of a moving coil to measure a specific electrical current or a current operation. The deflection is a mechanical rotation which is derived from the current forces.