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Question: A function of time given by \(\left( {\sin \omega t - \cos \omega t} \right)\) represents: 1) Simp...

A function of time given by (sinωtcosωt)\left( {\sin \omega t - \cos \omega t} \right) represents:

  1. Simple Harmonic Motion.
  2. Non-periodic Motion.
  3. Periodic but not simple harmonic motion
  4. Oscillatory but not simple harmonic motion
Explanation

Solution

In this question one has to know to compare the given equation (sinωtcosωt)\left( {\sin \omega t - \cos \omega t} \right) with the general equation of Simple harmonic motion. If the equation matches with the general equation of Simple Harmonic Motion then the given equation is of SHM otherwise it is not.

Complete step by step solution:
The general form of SHM is given by:
y=Asin(ωt+ϕ)y = A\sin (\omega t + \phi );
We have been given the equation as:
y =(sinωtcosωt)\left( {\sin \omega t - \cos \omega t} \right);
Multiply the above equation on the RHS with2\sqrt 2 .
y=2(sinωt2cosωt2)y = \sqrt 2 \left( {\dfrac{{\sin \omega t}}{{\sqrt 2 }} - \dfrac{{\cos \omega t}}{{\sqrt 2 }}} \right);
Here the value12\dfrac{1}{{\sqrt 2 }}is equal tosinπ4=cosπ4\sin \dfrac{\pi }{4} = \cos \dfrac{\pi }{4}; Put this value in the above equation:
y=2(sinωt×cosπ4cosωt×sinπ4)y = \sqrt 2 \left( {\sin \omega t \times \cos \dfrac{\pi }{4} - \cos \omega t \times \sin \dfrac{\pi }{4}} \right);
Apply trigonometric property (sinacosbcosbsina)=sin(ab)(\sin a\cos b - \cos b\sin a) = \sin (a - b)in the above equation:
y=2(sin(ωtπ4))y = \sqrt 2 \left( {\sin (\omega t - \dfrac{\pi }{4})} \right);
The above equation is similar to the general equation for SHM which is:
y=Asin(ωt+ϕ)y = A\sin (\omega t + \phi );
Compare the above two equations with each other.
Here: - A=2A = \sqrt 2 ;ϕ=π4\phi = \dfrac{\pi }{4}
Hence the option 2,3 and 4 are ruled out as they are not depicting Simple Harmonic Motion.
After comparing the above two equations we came to the conclusion that the equation (sinωtcosωt)\left( {\sin \omega t - \cos \omega t} \right)represents Simple Harmonic Motion with a time period2πω\dfrac{{2\pi }}{\omega }.

Final Answer: Option “1” is correct. A function of time given by (sinωtcosωt)\left( {\sin \omega t - \cos \omega t} \right)represents Simple Harmonic Motion.

Note: In Simple Harmonic Motion there is a force which tries to bring back an object to its mean position this force is known as restoring force. In SHM the restoring force is proportional to the displacement of the object from its original or mean position. The direction of the force that is restoring in nature is always directed towards the mean position.