Question
Quantitative Aptitude Question on Ratio and Proportion
A fruit seller has a total of 187 fruits consisting of apples, mangoes and oranges. The number of apples and mangoes are in the ratio 5 : 2. After she sells 75 apples, 26 mangoes and half of the oranges, the ratio of number of unsold apples to number of unsold oranges becomes 3 : 2. The total number of unsold fruits is
Let the number of apples be 5x, mangoes be 2x, and the number of oranges be y. So, the total number of fruits is:
5x+2x+y=187 or 7x+y=187 (Equation 1).
After selling, the unsold apples are 5x−75, mangoes 2x−26, and oranges 2y. The ratio of unsold apples to unsold oranges is given as 3 : 2:
2y5x−75=23
Simplifying, we get:
2(5x−75)=3y or 10x−150=3y (Equation 2).
Now solve the system of two equations: 1. 7x+y=187 2. 10x−150=3y
From Equation 1, solve for y:
y=187−7x.
Substitute this into Equation 2:
10x−150=3(187−7x),
10x−150=561−21x,
31x=711,
x=23.
Now, substitute x=23 into Equation 1 to find y:
7(23)+y=187,
161+y=187,
y=26.
Now, the unsold fruits are: Apples : 5(23)−75=115−75=40.
Mangoes : 2(23)−26=46−26=20.
Oranges: 226=13.
The total number of unsold fruits are:
40+20+13=66.
Solution
Let the number of apples be 5x, mangoes be 2x, and the number of oranges be y. So, the total number of fruits is:
5x+2x+y=187 or 7x+y=187 (Equation 1).
After selling, the unsold apples are 5x−75, mangoes 2x−26, and oranges 2y. The ratio of unsold apples to unsold oranges is given as 3 : 2:
2y5x−75=23
Simplifying, we get:
2(5x−75)=3y or 10x−150=3y (Equation 2).
Now solve the system of two equations: 1. 7x+y=187 2. 10x−150=3y
From Equation 1, solve for y:
y=187−7x.
Substitute this into Equation 2:
10x−150=3(187−7x),
10x−150=561−21x,
31x=711,
x=23.
Now, substitute x=23 into Equation 1 to find y:
7(23)+y=187,
161+y=187,
y=26.
Now, the unsold fruits are: Apples : 5(23)−75=115−75=40.
Mangoes : 2(23)−26=46−26=20.
Oranges: 226=13.
The total number of unsold fruits are:
40+20+13=66.