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Question

Physics Question on Uniform Circular Motion

A frictionless track ABCDEA B C D E ends in a circular loop of radius R.AR. A body slides down the track from point AA which is at a height h=5cmh = 5 \,cm . Maximum value of RR for the body to successfully complete the loop is

A

5cm5 \,cm

B

154cm\frac{15}{4} cm

C

103cm\frac{10}{3} \,cm

D

2cm2 \,cm

Answer

2cm2 \,cm

Explanation

Solution

Potential energy of the body at point AA == kinetic energy of the body at point BB mgh=12mv2m g h=\frac{1}{2} m v^{2} gh=v22g h=\frac{v^{2}}{2} Velocity at lowest point in a vertical circle v=5Rgv=\sqrt{5 R g} gh=5Rg2g h=\frac{5 R g}{2} R=2h5R=\frac{2 h}{5} But h=5cmh=5\, cm R=2×55=2cm\therefore R=\frac{2 \times 5}{5}=2 \,cm