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Question: A fraction \(f_{1}\) of a radioactive sample decays in one mean life, and a fraction \(f_{2}\) decay...

A fraction f1f_{1} of a radioactive sample decays in one mean life, and a fraction f2f_{2} decays in one half life. Then

A

f1>f2f_{1} > f_{2}

B

f1<f2f_{1} < f_{2}

C

f1=f2f_{1} = f_{2}

D

Either of (1), (2) or (3) depending on the values of the mean life and half life

Answer

f1>f2f_{1} > f_{2}

Explanation

Solution

: Mean life, τ=1λ\tau = \frac{1}{\lambda}

And half life , T1/2=ln2λ=0.693λT_{1/2} = \frac{\ln 2}{\lambda} = \frac{0.693}{\lambda}

τ>T1/2\because\tau > T_{1/2}Greater fraction will decay in longer time. Hence, fraction decayed in one mean life must be greater than the fraction decayed in one half life i.e.

f1>f2f_{1} > f_{2}