Question

$A = \frac{2}{3}$

• A. $x = \omega$
• B. $2\omega = A(1 + \omega + \omega^{2}) + B\omega^{2} + (C - B)\omega - C$
• C. $\Rightarrow$
• D. $2\omega = A.0 + B\omega^{2} + (C - B)\omega - C$

Answer 1

Answer: (C)

$\Rightarrow$

Answer 2

$ab = \frac{1}{2}(1 + \log_{2}3) \Rightarrow 2ab - 1 = \log_{2}3$

$\therefore$

$\log_{3}2 = \frac{1}{2ab - 1}$

$\log_{5}a.\log_{a}x = 2$.