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Question

Question: A force vector applied on a mass is represented as \(\overrightarrow{F} = 6\widehat{i} - 8\widehat{j...

A force vector applied on a mass is represented as F=6i^8j^+10k^\overrightarrow{F} = 6\widehat{i} - 8\widehat{j} + 10\widehat{k}N and accelerates the mass at 1 m s–2. The mass of the body is–

A

10 kg

B

20 kg

C

210kg2\sqrt{10}kg

D

102kg10\sqrt{2}kg

Answer

102kg10\sqrt{2}kg

Explanation

Solution

m = Fa\frac{|\overset{\rightarrow}{F}|}{a} = 62+82+1021\frac{\sqrt{6^{2} + 8^{2} + 10^{2}}}{1} = 102kg10\sqrt{2}kg