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Question

Question: A force vector applied on a mass is represented as \(\overrightarrow{F} = 6\widehat{i} - 8\widehat{j...

A force vector applied on a mass is represented as F=6i^8j^+10k^\overrightarrow{F} = 6\widehat{i} - 8\widehat{j} + 10\widehat{k} and accelerates with 1m/s21m/s^{2}. What will be the mass of the body

A

102kg10\sqrt{2}kg

B

210kg2\sqrt{10}kg

C

10 kg

D

20 kg

Explanation

Solution

m=Fa=62+82+1021=200=102kgm = \frac{F}{a} = \frac{\sqrt{6^{2} + 8^{2} + 10^{2}}}{1} = \sqrt{200} = 10\sqrt{2}kg