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Question: A force produces an acceleration of \({a_1}\) in a body and the same force produces an acceleration ...

A force produces an acceleration of a1{a_1} in a body and the same force produces an acceleration of a2{a_2} in another body. If the two bodies are combined and the same force is applied on the combination, then the acceleration produced in it is
A. a1+a2{a_1} + {a_2}
B. a1+a2a1a2\dfrac{{{a_1} + {a_2}}}{{{a_1}{a_2}}}
C. a1a2a1+a2\dfrac{{{a_1}{a_2}}}{{{a_1} + {a_2}}}
D.a1a2\sqrt {{a_1}{a_2}}

Explanation

Solution

In this question, we will assume a force F and let it be applied on each of the two masses m1{m_1} and m2{m_2}separately. We will calculate the corresponding acceleration and then form a body having mass m = m1{m_1}+m2{m_2}. And then calculate the acceleration when the same force applied by using the formula F=ma.

Complete answer:
Let us assume two bodies having masses m1{m_1} and m2{m_2} and F be the force which is applied on the bodies separately.
We know that according to Newton’s second law of motion:
F=ma. (1)
Now on applying this on body of mass m1{m_1}, we have:
F = m1{m_1} a1{a_1}
On dividing both sides by m1{m_1}, we get:
m1=Fa1{m_1} = \dfrac{F}{{{a_1}}} (2)
Now on applying this on body of mass m2{m_2}, we have:
F = m2{m_2} a2{a_2}
On dividing both sides by m2{m_2}, we get:
m2=Fa2{m_2} = \dfrac{F}{{{a_2}}} (3)
The equivalent mass m = m1+m2{m_1} + {m_2}.
Now on applying equation 1 on this equivalent mass, we have:
F = (m1+m2{m_1} + {m_2})a
On dividing both sides bym1+m2{m_1} + {m_2}, we get:
a=Fm1+m2{a_{}} = \dfrac{F}{{{m_1} + {m_2}}}
Putting the value of m1{m_1} and m2{m_2}in above equation, we get:
a=FFa1+Fa2=a1a2a1+a2{a_{}} = \dfrac{F}{{\dfrac{F}{{{a_1}}} + \dfrac{F}{{{a_2}}}}} = \dfrac{{{a_1}{a_2}}}{{{a_1} + {a_2}}}

So, the correct answer is “Option C”.

Note:
In this question, you should know about the Newton law of motion, especially Newton’s second law. Newton’s second law states that acceleration produced in the body of mass m is directly proportional to force applied and inversely to the mass of the body. i.e. F = ma. If F is constant, the acceleration produced is inversely to mass of the body.