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Question: A force \(\overset{\rightarrow}{F} = 5\widehat{i} + 6\widehat{j} + 4\widehat{k}\) acting on a body, ...

A force F→=5i^+6j^+4k^\overset{\rightarrow}{F} = 5\widehat{i} + 6\widehat{j} + 4\widehat{k} acting on a body, produces a displacement S→=6i^−5k^.\overset{\rightarrow}{S} = 6\widehat{i} - 5\widehat{k}. Work done by the force is

A

10 units

B

18 units

C

11 units

D

5 units

Answer

10 units

Explanation

Solution

W=Fˉ.sˉ=(5i^+6j^+4k^)(6i^−5k^)=30−20=10W = \bar{F}.\bar{s} = (5\widehat{i} + 6\widehat{j} + 4\widehat{k})(6\widehat{i} - 5\widehat{k}) = 30 - 20 = 10J