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Question

Physics Question on mechanical properties of solids

A force of 6×106Nm26 \times 10^{6} Nm ^{-2} required for breaking a material. The density ρ\rho of the material is 3×103kgm33 \times 10^{3} kg m ^{-3}. If the wire is to break under its own weight, the length of the wire made of that material should be (take g=10ms2g=10 \,ms ^{-2} )

A

20 m

B

200 m

C

100 m

D

2000 m

Answer

200 m

Explanation

Solution

When a wire is pulled it stretches (undergoes strain) upto a certain limit the amount it stretches is proportional to the load divided by the cross-sectional area of the wire. Stress = Force  Area =mgA=VρgA=LAρgA=\frac{\text { Force }}{\text { Area }}=\frac{m g}{A}=\frac{V \rho g}{A}=\frac{L A \rho g}{A} \therefore Stress =Lρg=L \rho g Given, stress =6×106Nm2=6 \times 10^{6} Nm ^{-2} ρ=3×103kgm3\rho =3 \times 10^{3} kg m ^{-3} g=10ms2g =10 \,ms ^{-2} L= stress ρgL =\frac{\text { stress }}{\rho g} =6×1063×103×10=\frac{6 \times 10^{6}}{3 \times 10^{3} \times 10} =2×102=200m=2 \times 10^{2}=200 \,m