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Question: A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, th...

A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, then impulse is

A

0.15×10−3N−s0.15 \times 10^{- 3}N - s

B

0.98×10−3N−s0.98 \times 10^{- 3}N - s

C

1.5×10−3N−s1.5 \times 10^{- 3}N - s

D

2.5×10−3Ns2.5 \times 10^{- 3}Ns

Answer

1.5×10−3N−s1.5 \times 10^{- 3}N - s

Explanation

Solution

Im⥂pulse=force×time\text{Im} ⥂ \text{pulse} = \text{force} \times \text{time} =50×10−5×3= 50 \times 10^{- 5} \times 3

=1.5×10−3N−S= 1.5 \times 10^{- 3}N - S