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Question: A force of 5 N acts on a 15 kg body initially at rest. The work done by the force during the first s...

A force of 5 N acts on a 15 kg body initially at rest. The work done by the force during the first second of motion of the body is

A

5 J

B

56J\frac { 5 } { 6 } J

C

6 J

D

75 J

Answer

56J\frac { 5 } { 6 } J

Explanation

Solution

W=Fs=F×12at2W = F s = F \times \frac { 1 } { 2 } a t ^ { 2 } [froms=ut+12at2]\left[ \operatorname { from } s = u t + \frac { 1 } { 2 } a t ^ { 2 } \right]

W=F[12(Fm)t2]W = F \left[ \frac { 1 } { 2 } \left( \frac { F } { m } \right) t ^ { 2 } \right]