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Question: A force of \(2\widehat{i} + 3\widehat{j} + 4\widehat{k}\mspace{6mu} N\)acts on a body for 4 second, ...

A force of 2i^+3j^+4k^6muN2\widehat{i} + 3\widehat{j} + 4\widehat{k}\mspace{6mu} Nacts on a body for 4 second, produces a displacement of (3i^+4j^+5k^)m.(3\widehat{i} + 4\widehat{j} + 5\widehat{k})m. The power used is

A

9.5 W

B

7.5 W

C

6.5 W

D

4.5 W

Answer

9.5 W

Explanation

Solution

P=Fst=(2i^+3j^+4k^)(3i^+4j^+5k^)4P = \frac { \vec { F } \cdot \vec { s } } { t } = \frac { ( 2 \hat { i } + 3 \hat { j } + 4 \hat { k } ) \cdot ( 3 \hat { i } + 4 \hat { j } + 5 \hat { k } ) } { 4 } =384=9.5 W= \frac { 38 } { 4 } = 9.5 \mathrm {~W}