Question
Question: A force of \(2\widehat{i} + 3\widehat{j} + 4\widehat{k}\mspace{6mu} N\)acts on a body for 4 second, ...
A force of 2i+3j+4k6muNacts on a body for 4 second, produces a displacement of (3i+4j+5k)m. The power used is
A
9.5 W
B
7.5 W
C
6.5 W
D
4.5 W
Answer
9.5 W
Explanation
Solution
P=tF⋅s=4(2i^+3j^+4k^)⋅(3i^+4j^+5k^) =438=9.5 W