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Question

Physics Question on Power

A force of 2i^+3j^+4k^2\hat{i}+3\hat{j}+4\hat{k} NN acts on a body for 44 second, produces a displacement of (3i^+4j^+5k^)\left(3\hat{i}+4\hat{j}+5\hat{k}\right) mm. The power used is

A

9.5 W

B

7.5 W

C

6.5 W

D

4.5 W

Answer

9.5 W

Explanation

Solution

The correct option is(A): 9.5 W.
velocity =displacementtime=\frac{\text{displacement}}{\text{time}}
=34i^+74j^+54k^=\frac{3}{4} \hat{i} + \frac{7}{4} \hat{j} + \frac{5}{4} \hat{k}
=3i^+j^+54k^=\frac{3 \hat{i}}+\hat{j}+\frac{5}{4 \hat{k}}
P=FVP=F \cdot V
=(2i^+3j^+4k^)(34i^+j^+54k^)=(2 \hat{i}+3 \hat{j}+4 \hat{k}) \cdot\left(\frac{3}{4} \hat{i}+\hat{j}+\frac{5}{4} \hat{k}\right)
=2×34+1×3+4×54=2 \times \frac{3}{4}+1 \times 3+4 \times \frac{5}{4}
=1.5+3+5=9.5W=1.5+3+5=9.5\, W.