Question
Physics Question on Power
A force of 2i^+3j^+4k^ N acts on a body for 4 second, produces a displacement of (3i^+4j^+5k^) m. The power used is
A
9.5 W
B
7.5 W
C
6.5 W
D
4.5 W
Answer
9.5 W
Explanation
Solution
The correct option is(A): 9.5 W.
velocity =timedisplacement
=43i^+47j^+45k^
=+3i^j^+4k^5
P=F⋅V
=(2i^+3j^+4k^)⋅(43i^+j^+45k^)
=2×43+1×3+4×45
=1.5+3+5=9.5W.