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Question: A force of 150N produces an acceleration of \(2m{s^{ - 2}}\) in a body and a force of 200N produces ...

A force of 150N produces an acceleration of 2ms22m{s^{ - 2}} in a body and a force of 200N produces an acceleration of 3ms23m{s^{ - 2}}. The mass of the body and the coefficient of kinetic friction are
A. 50kg;0.1
B. 25kg;0.1
C. 50kg;0.5
D. 50kg;0.2

Explanation

Solution

Friction: Friction force is a force which works opposite of applied force. In which friction is working between two surfaces, sliding or rolling. There are two types of friction:
A. Static friction
B. Kinetic friction

Complete step by step answer:
Kinetic friction: The friction which is work on moving objects is known as kinetic friction.
Given in question,
F1=150N{F_1} = 150N
a1=2ms2{a_1} = 2m{s^{ - 2}}
F2=200N{F_2} = 200N
a2=3ms2{a_2} = 3m{s^{ - 2}}
g=10ms2g = 10m{s^{ - 2}}
Find,
m= ?
μ\mu =?
According newton's second law with friction,
ma=Fμmgma = F - \mu mg …(1)
Put the value in equation 1,
m×2=15010μmm \times 2 = 150 - 10\mu m …(2)
m×3=20010μmm \times 3 = 200 - 10\mu m …(3)
Subtracting equation 2 from equation 3

m×3=20010μm m×2=15010μm m=50  m \times 3 = 200 - 10\mu m \\\ \underline {m \times 2 = 150 - 10\mu m} \\\ m = 50 \\\

Put the value of m=50m = 50 in equation 2
50×3=20010×50μ50 \times 3 = 200 - 10 \times 50\mu
500μ=200150500\mu = 200 - 150
500μ=50500\mu = 50
μ=50500\mu = \dfrac{{50}}{{500}}
μ=0.1\mu = 0.1

So, the correct answer is “Option A”.

Note: Static friction is working on the object which is on rest while the kinetic friction is working on motion. Friction is equal and opposite of applied force.