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Question: A force \(\vec { F } = 3 \hat { i } + \hat { c j } + 2 \hat { k }\) acting on a particle causes a di...

A force F=3i^+cj^+2k^\vec { F } = 3 \hat { i } + \hat { c j } + 2 \hat { k } acting on a particle causes a displacement S=4i^+2j^3k^\vec { S } = - 4 \hat { i } + 2 \hat { j } - 3 \hat { k } in its own direction. If the work done is 6J, then the value of c will be

A

12

B

6

C

1

D

0

Answer

12

Explanation

Solution

=12+2c6= - 12 + 2 c - 6

Work done (given)

\therefore 12+2c6=6- 12 + 2 c - 6 = 6 \Rightarrow c=12c = 12