Question

A force $F =\left(5+3 y^2\right)$ acts on a particle in the $y$-direction, where $F$ is in newton and $y$ is in meter The work done by the force during a displacement from $y=2 m$ to $y=5 m$ is___$J$

Answer 1

The correct answer is 132.
F=5+3y2
W=2∫5​(5+3y2)dy
=[5y+33y3​]25​
=132J