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Question: A force F = kt(τ - t) acts on a particle of mass m, which is at rest at t = 0 where k is a constant....

A force F = kt(τ - t) acts on a particle of mass m, which is at rest at t = 0 where k is a constant. Find the momentum of the force when the action of the force is discontinued.

A

kτ32\frac { \mathrm { k } \tau ^ { 3 } } { 2 }

B

C

D

Answer

Explanation

Solution

∆p = Fdt=0τkt(τt)dt=kτ32kτ33=kτ46\int \mathrm { Fdt } = \int _ { 0 } ^ { \tau } \mathrm { kt } ( \tau - \mathrm { t } ) \mathrm { dt } = \frac { \mathrm { k } \tau ^ { 3 } } { 2 } - \frac { \mathrm { k } \tau ^ { 3 } } { 3 } = \frac { \mathrm { k } \tau ^ { 4 } } { 6 }.