Question

A force $F$ acts between sodium and chlorine ions of salt (sodium chloride) when put $1cm$ apart in air. The permittivity of air and dielectric constant of water are $\varepsilon_{0}$ and $K$ respectively. When a piece of salt is put in water electrical force acting between sodium and chlorine ions $1cm$ apart is

• A. $\frac{F}{K}$
• B. $\frac{FK}{\varepsilon_{0}}$
• C. $\frac{F}{K\varepsilon_{0}}$
• D. $\frac{F\varepsilon_{0}}{K}$

Answer 1

Answer: (A)

$\frac{F}{K}$

Answer 2

When put 1 cm apart in air, the force between Na and Cl ions = F. When put in water, the force between Na and Cl ions $= \frac{F}{K}$