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Question

Physics Question on Newtons Laws of Motion

A force F=75NF = 75\, N is applied on a block of mass 5kg5\, kg along the fixed smooth incline as shown in figure. Here gravitational acceleration g=10m/s2g = 10m/s^2. The acceleration of the block is

A

5ms25 \frac{m}{s^{2}} downwards the incline

B

5ms25 \frac{m}{s^{2}} upwards the incline

C

510ms2510 \frac{m}{s^{2}} downwards the incline

D

10ms210 \frac{m}{s^{2}} upwards the incline

Answer

10ms210 \frac{m}{s^{2}} upwards the incline

Explanation

Solution

Consider the force acting on the block as shown below

Given, F=75NF=75\, N
m=5kgm=5\, kg
Acceleration of the block
Fmgsin30=maF-m g \sin 30^{\circ} =m a
a=Fmgsin30m\Rightarrow a=\frac{F-m g \sin 30^{\circ}}{m}
a=755gsin305\Rightarrow a =\frac{75-5 g \sin 30^{\circ}}{5}
a=505=10m/s2a=\frac{50}{5}=10 m / s ^{2} upward to the inclined plane