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Question

Physics Question on Work Power and Energy

A forceF=20+10yF=20+10yacts on a particle in yy-direction where FF is in newton and y in meter. Work done by this force to move the particle from y=0y=0 to y=1 y=1 m is:

A

30J30J

B

5J5J

C

25J25J

D

20J20J

Answer

25J25J

Explanation

Solution

The correct option is (C) :25J25J