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Question: A force \((5\hat{i}+4\hat{j})\,N\) acts on a body and produces a displacement \(\vec{S}=(6\hat{i}-5\...

A force (5i^+4j^)N(5\hat{i}+4\hat{j})\,N acts on a body and produces a displacement S=(6i^5j^+3k^)m\vec{S}=(6\hat{i}-5\hat{j}+3\hat{k})\,m. The work done will be-
(1). 10J10J
(2). 20J20J
(3). 30J30J
(4). 40J40J

Explanation

Solution

According to the second law of motion, a force is required to change the state of rest or the state of motion of an object. Here, the force vector acts on a body due to which it covers the given displacement. The Work done is the scalar product of force and displacement vectors.

Formulas used:
W=FxW=\vec{F}\cdot \vec{x}

Complete answer:
The force is an interaction between two bodies which causes a change in the state or the motion of one of the bodies or both of them. Its SI unit is NN. Force is given by-
F=maF=ma
Here,FF is the force acting on an object
mm is the mass on which the force acts
aa is the acceleration of the body
The work done is the product of mass and displacement. Its SI unit is joules (JJ).
W=FxW=Fx
Here, WW is work done by force FF
xxis the displacement of the body
Since force and displacement are vector quantities, the work done is the scalar product of force vector and displacement vector.
W=FxW=\vec{F}\cdot \vec{x} --- (1)
Substituting the force vector and displacement vector in eq (1), we get,
W=(5i^+4j^)(6i^5j^+3k^) W=3020 \begin{aligned} & W=(5\hat{i}+4\hat{j})\cdot (6\hat{i}-5\hat{j}+3\hat{k}) \\\ & \Rightarrow W=30-20 \\\ \end{aligned}
W=10J\therefore W=10J

The work done by the force is 10J10J. So, the correct option is (A).

Note:
The scalar product of two vectors is a scalar quantity. The motion of an object is always in the direction of the force except for the frictional force which is opposite to the motion of a body. The work done on a body is stored as its energy. Kinetic energy is possessed by a body when it is in motion.